Answer by mathlove for Locus of the center of the circle of radius $a$,which...
Also since the point $(x_0,y_0,z_0)$ lies on the plane $\dfrac{x}{x_1}+\dfrac{y}{y_1}+\dfrac{z}{z_1}=0$,$\dfrac{x_0}{x_1}+\dfrac{y_0}{y_1}+\dfrac{z_0}{z_1}=0..................(2)$This is not correct....
View ArticleLocus of the center of the circle of radius $a$,which always intersects...
If the axes are rectangular, show that the locus of the center of the circle of radius $a$,which always intersects coordinate axes is$x\sqrt{a^2-y^2-z^2}+y\sqrt{a^2-z^2-x^2}+z\sqrt{a^2-x^2-y^2}=a^2$Let...
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